Usually, the problem is simplified to a threshold test, like: Does this tour have path length < X? These kind of problems are equivalently difficult to produce solutions for in the general case, but are straightforward to verify.
Usually, the problem is simplified to a threshold test, like: Does this tour have path length < X? These kind of problems are equivalently difficult to produce solutions for in the general case, but are straightforward to verify.
For Traveling Salesman, this means that given the best tour for an N-city graph, the best tour for the same graph augmented by a single vertex could be entirely different.
And this is easy to then contrast with, say, sorting, to counter the earlier objection.
We can split the set into two, sort the two parts individually and then trivially merge the results. We cannot split the cities into two, solve the traveling salesman problem, and then easily merge the results.
And adding a new element to a sorted list is just a linear insertion.