m = 10^9.10^5 / (10*100) = 10^11 kg of water. = 10^8 m^3
This is not a big reserviour, being 1/20th of the size of Warragamba dam's reserviour (in Sydney). One valley could provide 20GW for a day. Compare that with demand for where I live:
http://www.aemo.com.au/Electricity/Data/Price-and-Demand/Pri...
Peak demand for 7.5M people is 9GW, with an average closer to 7GW. One valley could provide overnight storage for over 20 million people, with first world demands (all of Australia). The limitation is transmission and generating/pumping capacity, rather than storage volume.