I only knew(and liked) C reasonably well before Rust. And nothing felt obscure when I started learning it.
I can only remember not getting what `||` meant (in the context of defining a closure without args). The positional meaning of `||` and `&&` is the only thing, I can recall right now, that can be considered obscure syntactically (for C developers at least) . They should have gone with literal `and`/`or` for the operators IMHO.
// prints 'true'
println!("{}", true||(||true)()||(||true)());
// prints '()'
println!("{:?}", (||||||||||())()()()()());
That's true. But put your self in the mind of a C developer looking at Rust code for the first time:
if a || b {
println!("True");
}
Then:
thread::spawn(|| println!("Hello from a thread!"););
----
IIRC, there are also cases where you have to write `& &` instead of `&&` to not confuse the compiler. That's a design/practical issue.
Both those issues would have been avoided if literal `and`/`or` were used.
I find it interesting how the only thing that momentarily confused me, as a C developer, about Rust syntax, was caused by Rust authors not wanting to syntactically deviate too much from C.