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I lack formal CS training: "0 0 2 0 1 2 1 0 1" is a sequence of 9 integers. Why would you allocate 256 bytes? Edifying post, thanks.

Your addresses in this simple instruction set are 8-bit; 256 bytes gives you a full 8-bit memory space.

Not every number is an integer. Could be a char or a short too. The sizes of those depends on the platform and if it's signed or unsigned.