No you don't. You might notice this by simply working with imaginary numbers. You might invent imaginary numbers for rotation [0].
Alternatively, consider the multiplication (x + yi)(a + bi), as the value (a + bi) performing a transformation on (x + yi). We want (x + yi)(a + bi) = xy - by + ayi + bxi. If we consider (x + yi) to be a 2 dimensional matrix (with basis 1 and i), we can write the above equation as a matrix multiplication:
[ x y ] [ a b ] = [ ax-by ; ay + bx]
-b a
Notice that [ a b ]
-b a
is just a rotation matrix multiplied by the scalar (a^2 + b^2).[0] That is, define a group (in the group-theory sense) of functions of rotations, denoted as xi for real numbers x, and a group of group of functions for sliding, denoted x for real numbers x. You might then notice that you can combine these groups in a field structure, that happens to have 1i * 1i = -1, and that the subfield of elements with no i component happens to be isomorphic the the reals.