Hacker News Reader

Comment by mato | Hacker News Reader

> A unikernel cannot do this. If the app is compromised and I don't notice and don't restart it...

I disagree. There's no reason such mitigations (not sure what exactly you're referring to) can't be implemented by the monitor process (ukvm in the Solo5/ukvm model).

I'd also argue that a normal kernel does not do any integrity checks on the code running in a user process, so the model is exactly the same.

> Even worse, the attacker could use it as leverage to infect other unikernel based instances of the app to gain some permanence against restarts by simply reinfecting when an instance goes down.

For that they'd need to break out of the virtual machine and into the hypervisor / monitor. Which is by no means impossible, but with careful design of unikernel-specific monitors can be much reduced. Of course, I'm by no means suggesting you should back your unikernels with a monitor along the lines of QEMU :-)

View on HN

1) You are in Ring 0. There is no defense unless you reimplement a normal Kernel to run a process in Ring 3 along with the monitoring process and capabilities management... etc

2) No, the attacker is most likely there because of some bug in the app, once in the network, it becomes harder to stop the attacker infecting other instances.

3) Hypervisors are not perfect. There are known instances of people infecting the host through the hypervisor.

1) Virtualized Ring 0 != Ring 0. See section 24.6 "VM-execution control fields" of the Intel SDM for details of the controls a hypervisor can use to modify guest behaviour.

2) The same applies to any application, not just unikernels.

3) I completely agree.

1) You are still on a Ring 0. On a normal operating system, an exploited app has a limited action range, depending on the system settings. A lot of exploits simply do not work because the operating system kills the process. On Ring 0, even virtualized, all these protections do not work. You have full control within the VM and you can't have some process within the VM to check this as it is equally vulnerable.

2) Yes but Unikernels do not provide special protection against this either.

> On a normal operating system, an exploited app has a limited action range

Minor point, but this seems to be a bit lost in the discussion: Generally 1 unikernel == 1 VM (or, virtualization-backed sandbox, the use of "virtual machine" brings too much baggage with it) == 1 application.

So, the attack scope for the class of attacks we're debating is equally limited to a single application, just like on a normal operating system.

Not quite.

When you write an exploit for a normal operating system application, you can't, for example, just write your payload into data memory and start executing it. You can't jump to the address of an array and have the CPU execute it's contents.

On a unikernel this sort of thing becomes trivial since everything is Ring 0 and all protections can be trivially disabled.

You can just write your payload into any arbitrary data field and your exploit only needs to jump to it, even with address randomization this can be exploited (ASLR and similar techniques do not prevent exploits, only make them harder)

The exploiting just becomes a whole lot easier.

It's not even remotely more secure than Ring 3 code running on a kernel that has strict capability enforcement.

> On a unikernel this sort of thing becomes trivial since everything is Ring 0 and all protections can be trivially disabled.

If the hypervisor sets the relevant VMCS control fields for the unikernel to cause a VMEXIT on (for example) a load of CR3 and any EPT violations and sets up the guest with a static set of read-only and executable (or in fact, with EPT you could even do execute-only) pages then there is no way the unikernel can disable these protections.

Having said that, I'm not arguing that running unikernels in Ring 0 is the best approach for security, just that it's not impossibly insecure.

With ukvm we're also looking into running all of the unikernel in (virtualized) Ring 3 with nothing running in Ring 0. However, this needs more experimentation since with x86 you can't (for example) easily handle legitimate exceptions (e.g. divide by zero) from Ring 3.

Reply on news.ycombinator.com