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Comment by scotty79 | Hacker News Reader

    f(x)=a*x^2

    f(2*x)=a*(2*x)^2=a*4*x^2=4*a*x^2=4*f(x)

Doubling the argument quadruples the value of quadratic function.

Try again using order of operations. It does not expand to (2*x)^2, it is simply 2x^2.

To say it another way: 4x^2 != 2x^2