This is incorrect. FlushFiewOfFile and FlushFileBuffers only guarantees that contents are written to the physical media. It is not necessary (well, it is not supposed to be necessary) to call either of these functions for other processes to be able to see the changes.

The whole point of a cache is that if A writes something, and then B reads it after A finishes writing it, B should see the results of A's modification. Whether it has been flushed to the physical media is irrelevant, because if it hasn't the cache manager can still serve the contents directly from the cache. And a call to Flush is not necessary for that.

So, the OP's change is not missing anything. As the article explains, it is in fact the Windows kernel that is behaving incorrectly (which was also confirmed by people who work on the windows kernel).