I don't understand your syntax on the for-in. Is there some magic on an array that takes a closure and is nonobvious? Or is there a syntactic issue with the code in your comment?
for i=0;i<10;i++ { setTimeout(() => console.log(i), 100); }
The second won't do that, since the "view" var isn't "mutated" between calls.
1) view is immutable in both cases
2) GGP is returning in a void block so both sets of code will fail
3) there is really no difference except iteration vs function calls as far as I can tell, you can iterate arrays and use higher order functions built into arrays... which seems normal
4) you can only access the index in (1) by calling .enumerated() I suppose.
To address this argument: the fact that a ‘return’ within a loop exits the enclosing function and a return from within a closure exits the closure is not a Swift problem.