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Comment by neon_electro | Hacker News Reader

Care to elaborate? This is not something I would've intuited.

Presumably they are referring to length extension attacks. You can't pull them off if you truncate. https://en.m.wikipedia.org/wiki/Length_extension_attack

Generally though length ext attacks have a solution - HMAC, which is much more secure than truncate.

The more you truncate, the more vulnerable you are to birthday attacks (practically speaking you would have to truncate quite a lot)

The canonical solution is SHA-512/256 i.e 512 truncated to 256 bits where "nothing is lost" compared to SHA-256 and something is gained. It might even be faster (due to the 64-bit word formulation of SHA-512) in some implementations.

Generally is faster (fewer rounds per byte). If you have 256 bits available for your hash and you're on a 64 bit architecture, I've yet to see a case where you're not better off for performance and security choosing SHA-512/256 over SHA-256, assuming you have the choice.

Is this still true? I understood SHA256 to be faster than SHA512 due to hardware acceleration on current CPUs; dedicated instructions exist for the former but not the latter.

It seems like it's not true on a MacBook with the Apple M1 processor; SHA-256 is now significantly faster. It still seems to be true on a couple of Intel machines I have access to.

Googling i noticed there seems to be a bug in openssl where it does not use optimized sha-512 on m1 (but does for sha256) - https://github.com/openssl/openssl/issues/14897 so that might be the explanation.

Also i think the length of the input matters when comparing sha256 vs sha512.

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