So you can make a grid with less than 40 quantum atom pairs, each of which is coupled in some way to another atom, and since measuring one atom guarantees the other atom is in the opposite state, you can bypass Heisenberg uncertainty.

But wait. To solve an NP problem of size n, you need square(n) atoms. But 40 atoms is barely more than 36, so you can solve a NP problem of size 6, which is easy and possible.

I think brute force on an NP problem is factorial(n) So factorial(6) == 6 ! == 6 * 5 * 4 * 3 * 2 * 1 == 720.

Am I misunderstanding something here ?