1/0 is undefined and 1/-0 is also undefined.
what we have is lim(x->0+) 1/x = +inf and lim(x->0-) 1/x = -inf
what we have is lim(x->0+) 1/x = +inf and lim(x->0-) 1/x = -inf
however, it is irrelevant to the fact that a commenter was disagreeing because they had confused ieee-754 division with the division operation on so-called 'real' numbers