That said, if you're all in on it I imagine that the front-end could pretty aggressively target that, much like how rust uses no alias.
That said, if you're all in on it I imagine that the front-end could pretty aggressively target that, much like how rust uses no alias.
References need to be specified as mutable if mutation is needed (i.e. `&mut T` instead of just `&T`). Using immutable references is also encouraged from the borrow checking rules; having a second reference (either mutable or immutable) alive at the same time as a mutable one is a compiler error, but using multiple immutable references at the same time is fine. (Pointers are the same way, but not really used much outside of bridging with unsafe Rust, since they can be null and therefore can't be dereferenced outside of `unsafe` blocks).
This is certainly the case in c++: distinct objects have distinct addresses, so to remove a copy the compiler has to prove that the aliasing is not observable which is hard.
But does rust have the same guarantee?
I honestly don't understand what you've said here at all. I'm not familiar with what "observable" means in this context, and googling "observable aliases programming languages" didn't help clarify it (two results were articles about C/C++ aliasing, one of which used the term "observable" once but didn't seem to define it at all, and the other which was the Wikipedia article on "Aliasing (computing)" that didn't contain the term at all).
Even if I knew what "observable" meant, I think you might be missing a negation (or maybe including one you didn't mean to) somewhere; if addresses are "kinda considered observable", it's not obvious why it would be an issue to omit copies and "be observable". Maybe understanding what's meant by "observable" would shed some light on what you mean here, but naively, I don't understand how code that expects things to "kind of" hold a property would break if that property were somehow more strongly held.