How large would a ring have to be to have 1g at 1 rotation per day? (Edit: earth day)
That's the parameters of a "Banks Orbital" https://theculture.fandom.com/wiki/Orbital_(Wikipedia_versio...
Which is:
> For such an orbital to reproduce the equivalent to the Earth's gravity, whilst maintaining Earth's 24-hour period of rotation, it would need to have a diameter of approximately 3.71 million kilometres, and spinning at 486,000 km/hr.
I know that's true of Niven's ringworld, which is just unholy scale and parameters - 1 rotation like the earth does in a year, every 9 days! (1)
And so it cannot be made from atoms, something with "tensile strength similar to the strong nuclear force" is needed (2)
But is it true of Banks's more practical Orbital as well? This reference says yes: "No form of ordinary matter will support the tensions of a Banks Orbital's spin, so exotic matter is required." (3)
1) http://www.alcyone.com/max/reference/scifi/ringworld.html
https://www.orionsarm.com/eg-article/47e1bb1fc898c
"Using accelerated streams of projectiles or particles to either transfer momentum or support a large structure."
This is basically active super strong matter that requires uninterrupted continuous control, power supply and real time adjustments - or bad things happen very very quickly. What is there not to love?! ;-)
* Possible, not necessarily practical.
You have: (1 gravity) / (1/1440 * rpm)^2
You want: million km
* 1.854336
/ 0.5392766
You have: (0.5 gravity) / (1 rpm)^2
You want: m
* 447.12962
For 1 g at 1 RPM:
You have: (1 gravity) / (1 rpm)^2
You want: m
* 894.25925
You have: (1 gravity) / (3 rpm)^2
You want: m
* 99.362139
Also via GNU Units:
You have: sqrt(1 gravity / earthradius)
You want: revolution/day
* 17.060434
You have: 1 day / 17
You want: hour; minute; second
1 hour + 24 minute + 42.352941 second
That's about once every 84 minutes.
Which, I recognise is also roughly the orbital period for low-Earth orbit, that is, an object falling around the Earth without ever striking the surface. Though I think that may be a coincidence. Compare geosyncronous orbit (~42,000 km from Earth's centre), with the radius at which there is 1g of centrifugal acceleration at 1 revolution per 24 hours, ~2 million km.
Fun to play with however.
If you had a trans-ring commute, at 100 kph, that would take you about 6 years 7 months one way.
A jet aircraft operating at nearer 1,000 kph would cut that to a far more manageable 7 months. Though I'd still use it as a reasonable argument for return-to-office.
Ping times would still be about 38 seconds even for free-vacuum direct transmission, around the ring itself. Given lightspeed is reduced to about 66% of its in vacuo* value in fibre optics, you'd have almost exactly a 1 minute delay. Something to keep in mind during those Ring Zoom sessions.
It would be oriented so that the sun appears to rise just to the side of the ring - When it's overhead the arc of the ring would appear to be near the sun, but not eclipsing it. This is nearer to vertical than the sun over much of Earth much of the time.
You're quite a bit off.
It's actually a little under 4 million km; several times the diameter of the sun.