Stacking triangles for fun and profit
oranlooney.com
oranlooney.com
Of course I do agree that definitions in terms of power series and differential equations are less natural and require heavier mathematical machinery.
But: the "right-angled triangle" definitions have the severe drawback of only applying to a restricted range of angles, and their relationship to those higher-tech definitions is more indirect than necessary.
Instead, I claim that the One True Definition of the trig functions is: if you start with the point (1,0) and rotate it through an angle t (anticlockwise, which is conventionally the "positive" direction in maths) about (0,0), then the point where it ends up is (cos t, sin t).
This is just as simple, and just as geometrical, as the "triangle" definition. It leads directly to the differential-equation characterization (which in turn leads easily to the power series). For angles between 0 and pi/2, it's obviously equivalent to the "triangle" definition.
Can you get the addition theorems easily from this definition? Yes, and (again) without the severe drawback of only applying when all the angles involved are between 0 and pi/2 as for the "triangle" definition.
Start with a diagram showing the points (0,0), (cos t, 0), (0, sin t), (cos t, sin t). Now rotate the whole thing through an angle u about the origin. Obviously (0,0) stays where it is. (cos t, 0) just goes to cos t times (cos u, sin u), i.e., to (cos t cos u, cos t sin u). If you turn your head through 90 degrees it becomes clear that (0, sin t) similarly goes to (- sin t cos u, sin t sin u). And of course (cos t, sin t) goes to (cos t+u, sin t+u) since we have rotated it through an angle t and then through an angle u.
And now we're done, because the "vector addition" property the original diagram had remains true after rotation, so adding (cos t cos u, cos t sin u) to (- sin t cos u, sin t sin u) has to give you (cos t+u, sin t+u). And that's exactly the addition theorems.
(That may be hard to follow with no diagrams, but I think it's easier to follow than the triangle-stacking proof would be without diagrams, and with diagrams everything is pretty transparent.)
The right-angled-triangle definitions are traditional because historically trigonometry came before coordinates. But now we have coordinates and generally learn about them before we learn trigonometry, and at that point the point-on-the-unit-circle definitions are simpler, more general, and better suited for proving other things.
The point of the post is that you should define things in terms of what you care about, and then prove stuff about it. The sum:
Sum from n=0 to infinity of (-1)^n / (2n+1)! * x^(2n+1)
isn't something you should start with, it should be the punchline. Instead, you should start with angles (the thing you care about), then prove that they behave the same as that sum (what an incredible claim!).The post proposed "angles of the acute corners of right triangles" as the starting point. You've argued very well that "angles in the unit circle relative to (1, 0)" is a better starting point. Pedagogically, I think it's a wonderful starting point:
"Let's talk about angles. Just angles, nothing else. When you look at angles of actual objects, the side lengths are all different, which complicates matters. Since all we care about is the angle itself, not the side lengths, let's make all side lengths equal to 1. Etc. etc."
I claim it’s only because you and I have internalized them so well that they both seem intuitive, which is what allows you to prefer the coordinates approach due to its greater generality to negative angles.
In any case, as another commenter said, I think you basically agree with the author’s main point and are disagreeing with a minor point (which is to some extent a manner of taste).
Though it does occur to me to wonder what an alien in a very obviously hyperbolic universe would consider the most natural. Or one of the beings that lives in Greg Egan's universe with two time and two space dimensions.
Of course, you could always just define sin and cos for acute angles only and then extend the definition with trig identities, but that seems rather unmotivated too.
1. Define sin/cos as ratios in a triangle 2. Draw a unit circle with an appropriate triangle in the first quarter and note that for the vertex on the circle, x = cos alpha and y = sin alpha. 3. Assuming it holds for values of alpha > 90 deg, extend sin/cos definitions to match.
Don't quite remember how one got derivatives from that, because trig and calc were in separate modules. Possibly via the sum formula.
Negative (and imaginary) measurements make math better-behaved. (See also: quantum mechanics.)
Rectangular coordinates are suboptimal because they are arbitrary in a way that hides some of the symmetry of mathematics.
Your vector argument looks like a lot of algebra noise "without a diagram" because it relies on... triangles... for intuitive justification.
I just think lesson zero in the above article should have been these projections, and a simple "From this all angles can be defined as right triangles in your preferred coordinate system", and you're off to the races in any old direction.
This is not how I was taught it, and I'm retrospectively upset.
It's not clear that the geometric proof based on pictures with positive angles α and β also applies to a negative β. I think one should at least provide a separate picture of that case...
I mean, the blog post was about a pedagogically better suited construction of trig functions. If we allow negative side lengths, it's not really going to be intuitive anymore. At this point, you might just as well use the power series definition (or the one based on the complex exp function) since it makes things easy to prove.
The idea of negative measurements (meaning "opposite direction along a line") as is well understood before children study geometry. Kindergarteners learn "left" vs "right" and "forward" vs "backward".
I agree with other poster about the value of showing negative and positive lengths visually in the same diagram.
Now think about what happens if you increase p by a tiny bit. a moves tangentially. (This works very similar to how the tangent to a curve gives the change in y for a change in x.) So the vector of cos'(p), sin'(p) is given by a vector starting from a, at a right angle to 0a, and pointing in the positive direction.
Since the point a moves through 2pi distance while p goes from 0 to 2pi (the definition of measuring angles in radians) the speed of the point is 1, and so the vector of derivatives has length 1.
You can check easily that this makes cos'(p) = -sin(p) and sin'(p) = cos(p).
(If I were trying to present this stuff in a maximally-elegant order without too much regard for what order human brains like to learn things in, the order of things would be: complex numbers, calculus, trigonometry. Then we define something that we might initially call e(t) to satisfy the differential equation de/dt = ie, and observe that having e and e' at right angles means that |e| remains constant, which means that |e'| also remains constant, so if we start with e(0)=1 then we have a point moving at unit speed around the unit circle, etc. Keep the linkage between the geometrical and formal points of view there at all times. But I suspect this wouldn't be great paedagogically for the majority of students.)
I had the less common experience of learning some graphics programming prior to taking a trig class in school. "How do I draw a circle?" You sweep an angle from 0 to 360 (or 2*pi) and use sin() and cos() to get points on the unit circle, then multiply by your radius and plot them. For me the notion of sin and cos being coordinates of points on a unit circle was natural. Later when I had trig class it seemed really weird to define these functions as ratios of sides of a triangle. In particular you never talk about a side length as being negative. So no, it's not universal that the triangle definitions seem more obvious or make more intuitive sense.
I think this is important for people to understand. What seems easy or natural can depend on how your particular tree of knowledge was constructed.
The unit circle with key points labeled is still my go-to doodle; it is a beautiful set of concepts.
Before that it was just some weird function I needed to calculate angles in triangles…
Now, draw a tangent line perpendicular to the x axis and find the point B where your ray intersects the tangent line. The length of the segment from the origin to B will be the secant, the length of the segment from B to the x axis will be the tangent.²
Finally, draw the tangent line parallel to the x axis and find the intersection of the ray with that line at C. The length of the segment from C to the origin will be the cosecant and the segment from the y axis to C will be the cotangent.
You can use your basic trig identities and knowledge of similar triangles to verify the relationships between the functions and the triangles. Angles outside the first quadrant will give signed values that make sense if you consider segments going down or left to be negative (but down and left is positive).
⸻
1. I’m making reference to cartesian coordinates strictly for the sake of convenience since I’m using only words to describe a diagram.
2. I’m doing this from memory and really hoping I’m not mixing up the tangent, cotangent, secant and cosecant
It's a good post, and I agree--there is just no hope in getting students to develop any kind of intuition in math without starting from something really simple like the geometry of the problem. Plus, it's way more fun!
I've enjoyed trig since, and one of the few math topics I continue to use to this day.
I had learned to use some game graphics library (specifically DJGPP with Allegro, coding in C) and I was trying to make a 2d spaceship game, think like asteroids, where you can turn the ship and apply thrust. I couldn't figure out how to take the angle the ship was facing and get a direction to move. Basically I needed to understand the unit circle. I eventually found what I needed probably on some old internet forums. From that point on, trigonometry really started making sense to me.
Before or after 2009?
I fail to see how you can "see" finer than sin(h) -> 0 & cos(h) -> 1
From the limit definitions you actually need :
* (1-cos(h)) / h -> 0
* sin(h)/h -> 1
(which correspond to the derivatives at 0).
If you zoom in sufficiently at x = 0, f(x) = sin(x) looks indistinguishable from f(x) = x, whereas g(x) = cos(x) looks indistinguishable from g(x) = 1.
(also, sin(x) is negative approaching 0 from the left and positive approaching 0 from the right)
You can't use the plot as you only know the triangle definition yet. (And "looks indistinguidable" is rather handwavy).
> (also, sin(x) is negative approaching 0 from the left and positive approaching 0 from the right)
That only tells you that sin(0)=0
Curvature is inverse of radius.
Decreasing angle is equivalent to increasing radius, and this decreasing curvature. This, as angle decreases, the curve becomes close to a straight line, and that straight line approaches a vertical line.
As usual, 3B1B created a quintessential visualization and explanation.https://m.youtube.com/watch?v=S0_qX4VJhMQ
I perfectly understand that around 0, sin(x) ~ x and cos(x) = 1 + o(x) but it isn't obvious geometrically, unlike what the article implies.
From my point of view, increasing radius / decreasing curvature only gets you sin(x) -> 0 ; cos(x) -> 1, but that isn't enough to obtain the derivatives.
I found a geometric proof in [1] but that part is the longest and hardest of the page. I was wondering whether the author found a clearer way to express is.
[1] https://www.mathsisfun.com/calculus/derivatives-trig-proof.h...
EDIT: after looking at 3B1B's video, the "small" triangle d(sinΘ) by dΘ figure would be a better way to explain the derivative, rather than an "not hard to see geometrically" approximation that isn't enough to conclude.
As others have noted here, the geometric argument only works "intuitively" for acute angles and the functions have to be explicitly extended. Still, I hadn't seen this proof of the angle addition formula yet, and I found it neat.
From a point of view of formalisation, a power series based approach (either directly or via the complex exp function) as traditionally used is probably better, because going into analysis (especially complex analysis), you're going to need power series anyway. Geometry meanwhile is intuitive to us but you'd have to encode a bunch of Euclidean axioms and theorems beforehand, which you might not otherwise use. Also, for better or worse, many mathematicians aren't really taught axiomatic geometry (I wasn't at least).
He uses the angle addition formulas to derive the Pythagorean theorem, but this derivation only works because he predefined sine and cosine as odd and even functions, which hasn’t been proven
Sin(t) clearly has the same sign as t. (That's why it's called "sin" ;-) )
Go through Euclid's Elements (i.e. http://aleph0.clarku.edu/~djoyce/elements/bookI/bookI.html)
Read the definitions and then prove all the postulates yourself, in order.
Am I just misunderstanding something about this articles motivation? I’m pretty sure I learned the unit circle in high school trig, possibly even 7th grade geometry although my memory that far back is fuzzier; but we did lots of geometric constructions with straightedge and compass, and did basic geometric proofs using complementary angles etc, and my teacher was obsessed with triangles. I didn’t learn about series until Calc 2 in early undergrad.
I still use the unit circle to reconstruct various trig properties from memory.
See also "Early vs Late Transcendentals" in calculus pedagogy.
In mathematics, sine and cosine are trigonometric functions of an angle. The sine and cosine of an acute angle are defined in the context of a right triangle: for the specified angle, its sine is the ratio of the length of the side that is opposite that angle to the length of the longest side of the triangle (the hypotenuse), and the cosine is the ratio of the length of the adjacent leg to that of the hypotenuse.
The author's claim that other definitions are the "most common starting points" seems like a straw man.[0] https://en.wikipedia.org/wiki/Divine_Proportions:_Rational_T...
As the angles increase, the 2 triangles will no longer be inside the rectangle. Signs start to flip around and extra work is needed to show the sin(a+b) and cos(a+b) equations are sound. The bright side is this is a good asignment for the student.
Question: is there an easy, geometrical way to "show" that `cos(60º)=1/2` using the intuitive definition based on the trigonometric circle?
(I assume that by "the intuitive definition based on the trigonometric circle" you mean that (cos t, sin t) is the point at angle t on the unit circle. If you meant something else, then what follows may not be helpful.)
APPROACH 1
If you take the point (1,0) and rotate it anticlockwise through 60º about the origin, you get (cos 60º, sin 60º), by definition. Look at the triangle formed by (0,0), (1,0), and (cos 60º, sin 60º). The angle at the (0,0) vertex is 60º. The other two angles are equal because the triangle is isosceles (rotating a line segment doesn't change its length) so they must also be 60º since the angles in a triangle add up to 180º.
So now drop a perpendicular from (cos 60º, sin 60º) down to the horizontal side of the triangle; it lands at (cos 60º, 0), so cos 60º is the distance from (0,0) to that point, and 1-cos 60º is the distance from (1,0) to that point. But those distances are the same, by symmetry, and now we're done.
APPROACH 2
Draw the unit circle and inscribe a regular hexagon in it with (1,0) as one vertex. Divide it up into six triangles by drawing radii. As above, these are equilateral triangles.
So now look at the horizontal separation between the opposite points (-1,0) and (1,0). Obviously the distance is 2 units. But we can split it up a different way: we have a horizontal distance 1-cos 60º from either of those to the next point around the circle, then 1 from that to the next point, then 1-cos 60º back to the opposite point. So 2 = (1-cos 60º)+1+(1-cos 60º) and again we're done.
(But I think any proof of this particular thing is going to be basically about equilateral triangles more than it's about circles. It might be easier first to show that for angles between 0 and 90º the trig functions have their "traditional" definition in terms of right-angled triangles, and then bisect an equilateral triangle.)
Everything else is a brutish approximation.
Trisect a 36° angle.
The cosine of 60 degrees is one half of the edge divided by the radius, i.e. divided by the edge, therefore it is 1/2.
Instead, I find that the intuition that's sought is more to start by seeing exp(it) as being a generator of complex rotation---a tremendously beautiful and parsimonious bit of theory---and then seeing sin and cos as being 1-dimensional coordinate projections of that.
Then the series definitions are just cute ways of deriving that relationship formally.
Circles over triangles.
I'm hoping that's a typo, and should be:
> Now, the line EC is perpendicular to AD, and...
(Edit: although I vaguely recall in school doing that bit as the sum of the angles around point C)