I got 883, which is also very human. They just forgot to write one of the halves of 8
You can only get an 8 in the rightmost digit of the result by multiples of the rightmost digits, but 08 obviously gets you a 0, so fairly easy to see this is wrong.
(10a+b)(10c+d) = 100ac+10(ad+bc)+bd
Well… I was joking. Even more generally, multiplication by b in base b gives a zero at the end.
… and, in fact, ‘b in base b’ always looks like 10 anyway!