Question 10 is just crazy broken. I'm not a standards expert, but I don't think argv[0] is guaranteed to be big enough to hold the 7 characters (plus \0) of NewName (i.e., even if it is writable, it may not be big enough).
As the comments said, argv[0] does not have to point to writable memory, because argc can be 0. In this case argv[0] is supposed to be NULL, which would segfault the program.
If you had to solve this question (it would be better not to ask it, because you don't learn much), I think the solution:
argv[0] = "NewName";