No, deterministic means that given the same inputs—source code, target architecture, optimization level, memory and runtime limits (because if the optimizer has more space/time it might find better optimizations), etc—a compiler will produce the same exact output. This is what reproducible builds is about: tightly controlling the inputs so the same output is produced.

That a compiler might pick among different specific implementations in the same equivalency class is exactly what you want a multi-architecture optimizing compiler to do. You don't want it choosing randomly between different optimization choices within an optimization level, that would be non-deterministic at compile time and largely useless assuming that there is at most one most optimized equivalent. I always want the compiler to choose to xor a register with itself to clear it if that's faster than explicitly setting it to zero if that makes the most sense to do given the inputs/constraints.