Let's put some algebra/order into this...
Bellman-Ford works for any totally ordered group (G,+), such that a+b<=a+c if b<=c.
What logarithm does is just a order preserving homomorphism from (R,*) to (R,+).
What logarithm does is just a order preserving homomorphism from (R,*) to (R,+).
No comments yet.