School kids measure distance to the Moon
technologyreview.com
technologyreview.com
If NASA really did fake the Moon landings, they did a bloody good job!
If you want to know how to calculate the distance, let me know and I'll write something about it.
PS: A pendulum and a calendar and a stopwatch or clock?
More later.
Now, what do we know? If we have a calendar that marks full moons, we know how often the occur and therefore we know w. What about the stuff involving GM? Well, now construct a pendulum. Standard formulae again but let's do it from scratch again. Length L, angular displacement a: vertical displacement is negligible to first order, so for small displacements the restoring force just comes from the tension in the string. To first order again, that equals the gravitational force on the mass, so the horizontal component of the acceleration is GM/r^2.La where r is the radius of the earth. So, measure the period of the pendulum (and of course its length); that tells us a and therefore GM/r^2. So provided we know r we now have GM and therefore R, and we're done.
So, one remaining question for RiderOfGiraffes: are you happy to look up r in a reference book for this exercise, or do you have a classroom-friendly way of getting that by simple observation and calculation too?
I guess, then, in addition to the pendulum, stopwatch and calendar we also need a ruler. We can use these to measure the size of the Earth directly using either the method of Eratosthenes (who also created the sieve for finding primes, and invented the system of latitude and longitude) or using the method used by Abu al-Rayhan al-Biruni.
That last, by the way, is cool, and I intend to use it in my next maths masterclass field trip.
The pendulum method gives the equation
l L^2 R^2 = P^2 D^3
l = pendulum length (assume 1m)
P = pendulum period (roughly 2s)
L = Lunar orbital time (27.32 * 86400)
R = Radius of the Earth
D = Distance to the Moon
Now we also know that in a total Lunar eclipse the Moon moves through the Earth's shadow. Assume it moves directly through the center. Measure the time for the Moon to move from touching the umbra to completely exiting the umbra. The distance it moves is then pretty much one Earth diameter, because the apparent sizes of the Sun and Moon are the same.So R/D = (T/2)(2pi/L) where T is the transit time, and turns out from observations to be around 12500 seconds.
Combining these equations we get:
D = l*(pi*T/P)^2
R = l*pi^3*T^3/(L*P^2)
They turn out pretty well.http://www.ted.com/index.php/talks/clifford_stoll_on_everyth...