Comment by Confusion | Hacker News Reader

Comment by Confusion | Hacker News Reader

Parent Full thread

The point of the OP is that if a program has chosen bash to be handler of untrusted user data, then the program has made the wrong choice, because bash is clearly (hindsight!, I'm not claiming I wouldn't have made the same choice) not designed or that purpose. A handler for untrusted user data should be a program specifically designed for that purpose, which should receive the data directly.

Similarly, if a Ruby or Perl script decides to call out to bash with untrusted user data, it's their mistake to trust bash with it, not bash's mistake that it wasn't designed for that use case.

It's perfectly possible to protect against this attack: don't call a generic program with untrusted user data.

So ruby and perl are specifically designed to be a handler of untrusted data?

How do I know what other programs are designed for such a task? What's a "generic program"? At this day and age, it is expected that pretty much all software ought to be designed with security in mind (not that it always is). Because any piece of "generic software" (or just software) is otherwise going to be exploited. Especially on platform where double-clicking a file is the expected way to open it.

More importantly, the point we are making is that we're not expecting bash to "handle" anything. It gets some data. It's not supposed to do anything with it on its own. Period.

> So ruby and perl are specifically designed to be a handler of untrusted data?

Perl actually is when used in taint mode. http://perldoc.perl.org/perlsec.html

Yes and no. You can still unintentionally call out to bash if you, say, protect your PATH:

  $ x='() { :;}; echo vulnerable'  perl -t -le'$ENV{PATH}="/bin";print `:;date`'
  vulnerable
  Sat Sep 27 10:51:12 PDT 2014

Reply on news.ycombinator.com