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Comment by ithinkso | Hacker News Reader

Nope, normality is necessary.

>>All that is needed for every work to appear is that each digit occur at least once.

Counter example would be a=0,123456789010011000111000011110000011111....

Normality is not necessary. Counter-counter example is the digits of pi in groups of 1, 2, 3... with strings of zeros in between:

   3.0140015900026530000....

this number is obviously nor normal since 0 occurs with greater frequency than any other digit. But if pi is normal, then this sequence contains all finite sequences too.

Each base 10 digit occurs at least once in your number. It's not obvious to me that each base b digit occurs at least once for all bases b in your number.

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