One other difference on modern compilers relating specifically to character arrays:

This will work fine:

    char arr[] = "stuff";

    printf("arr:%s\n", arr);
    arr[0] = 'b'; arr[1] = 'l';
    printf("arr:%s\n", arr);

arr is allocated on the stack (not heap, sorry about the mistake) and is mutable.

But the following will segfault:

    char* ptr = "stuff";

    printf("ptr:%s\n", ptr);
    ptr[0] = 'b'; ptr[1] = '1';
    printf("ptr:%s\n", ptr);

Strings are allocated in the read-only data segment. Technically you can only write const char* ptr = "stuff", but due to wanting to remain backward compatibile, gcc will let you write the above and not even warn you unless you use -Wall or similar.