Just out of curiosity, why'd you leave? MSR sounds pretty great.
576 karma · joined August 7, 2016
E = mc^2
∆m = ∆E/c^2
So really, what's ∆E? A hyper hand-wavy estimate: ∆E = Q = mc∆T (c being specific heat)
Specific heat by mass is really hard to predict, but by moles it is fairly constant, well within an order of magnitude. So we'll discuss mass in moles. m = neutron star moles
m = (mass of neutron star / mass of neutron) / Avogadro's #
m = 2.9580163e33 mol
c = 24 J / (mol * K)
∆T = 1e12 K - 1e6 K
→ ∆E = 24 * 2.9580163e33 * (1e12 - 1e6) J = 7.0991681e45 J
Substituting that back into the original, as a neutron star cools: ∆m = 7.0991681e45 J / c^2 = 7.89888982e28 kg
Which is like 2.6% of the mass of the original star, so a pretty solid chunk. But that number is pulled out of my ass—I am not a physicist.But there are even more weird effects going on, due to the warping of gravity the mass of neutron stars can be up to 20% less than you'd expect based on its baryonic (neutron) constituents (questions 4 and 7):
https://www.astro.umd.edu/~miller/teaching/questions/neutron...
This whole channel will be up your alley, but this video and "The Real Meaning of E=mc^2" one directly answer your question.
http://www.cornell.edu/video/playlist/nima-arkani-hamed-on-f...
Introduction ends and Nima starts about 4 minutes into the first lecture. :)