1,525 karma · joined May 19, 2009
https://247wallst.com/special-report/2020/10/05/cities-where...
More recent data here: https://github.com/washingtonpost/data-police-shootings
I would think you'd want at most one certificate authority per customer rather than per database. Why am I wrong?
I also note that seatbelts and airbags have undergone decades of engineering refinement; give that time to your admins, and your experience will be equally frictionless. Don't expect it to be done as soon as the download finishes.
Unrelated: what has your experience been using igneous-linearizer to help understand other people's code?
My own town (60,000+) lost its paper more than ten years ago.
Was that not the general experience?
Agreed. I expect to live to grieve the loss of New Orleans, and I'm not young.
In those pre-internet times, it also surfaced a problem with that environment: a sibling who vehemently averred to facts they did not have. They have since matured to be sufficiently tethered to reality to be an excellent parent and employee, but now cherry pick the internet for justification of social policy preferences.
From the article:
The Month-Item. — If it begins or ends with a vowel, subtract the number, denoting its place in the year, from 10. This, plus its number of days, gives the item for the following month. The item for January is ‘0’; for February or March (the 3rd month), ‘3’; for December (the 12th month), ’12.’ [So, for clarity, the required final numbers after division by 7 are January, 0; February, 3; March, 3; April, 6; May, 1; June, 4; July, 6; August 2; September, 5; October, 0; November, 3; and December, 5.]
My attempt to implement:
For January, the preceding month is December, which neither begins nor ends with a vowel, so I do not subtract 10. The days in December are 31, so 12+31 = 43 mod 7 = 1, not the 0 of the article.
For February, the preceding month is January, which ends in a vowel, so I subtract 1 from 10, giving 9, add the days in January 1+31 = 32 mod 7 = 4, not the 3 of the article.
For March, the preceding month is February, which ends in a vowel, so I subtract 2 from 10 giving 8 and add February's 28 days 8+28 = 36 mod 7 = 1, not the 3 of the article. Had I used a leap year 29 for the days in February at this step the result would be 2, which still does not match the article result. Since the article has a constant result for March, it is either always using 28 or always using 29 days in February.
For April, the preceding month is March, which neither begins nor ends in a vowel so I do not subtract it from 10. 31 days in March gives 3+31 = 34 mod 7 = 6, which does match the article result.
For May, the preceding month is April, which starts with a vowel, so I subtract its position from 10, 10-4 = 6, add April's 30 days 6+30 = 36 mod 7 = 1 which does match the article.
For June, the preceding month is May, ending in a vowel, so I subtract May's 5 from 10, and adding May's 31 days gives 5+31= 36 mod 7 = 1 which does not match the article.
This should suffice to illustrate my misunderstanding; what have I got wrong?
[edit: typos]
2. When intentionally writing perl, half the time my "perl -c foo.pl" complains about syntax or badly used names (usu. misspellings), with the typo to correct being obvious. As a practical matter, it's not a problem.
I see a lot of semicolons in that ocr output, which might be cheating.