As one would expect. The deferred code runs after the normal code in the function has ended, and before the calling code has resumed. Named return values are in scope and can be read and modified.
Try it and see: https://play.golang.org/p/1ozFWDj15a
Try it and see: https://play.golang.org/p/1ozFWDj15a
If you mean in the same context then, no.
So I think that means I was asking about execution in the same context (as in memory context), unless you mean stack frame by context, in which case, I think i understand that because the caller returns the value of the deferred, they are in the same stack frame, and nothing else could insert in that frame between them. I'm not sure you know what i mean, but do i have it about right?
I don't really understand this, but i think I'm getting somewhere.
This simple example should explain everything:
package main
import "fmt"
func function1() {
defer fmt.Println("function1: defer a")
fmt.Println("function1: inside")
defer fmt.Println("function1: defer b")
}
func main() {
fmt.Println("main: before function1")
function1()
fmt.Println("main: after function1")
}
Here is the output: main: before function1
function1: inside
function1: defer b
function1: defer a
main: after function1
All defers run in LIFO order at the point when a function returns before the function returns execution back to the caller.