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But what about unsigned char? It is guaranteed to have CHAR_BIT bits, where CHAR_BIT is at least 8. If CHAR_BIT is greater than 8, then uint8_t cannot be typedef'd to unsigned char.

I've stopped programming in C if I can help it. It's a crazy language with support for crazy machines.

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If CHAR_BITS is greater than 8, then uint8_t cannot be defined because CHAR_BITS is defined as the width of the smallest object that is not a bit-field. If uint8_t exists, it must be the same width as unsigned char.

It must have the same width as unsigned char in that scenario, but that does not make it unsigned char. § 6.5 of C11 only allows casting to "a character type" (and a few cases irrelevant in this context), not "a type of CHAR_BITS width". There's no requirement that uint8_t is a typedef for unsigned char.

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