Unfortunately, most infinite-precision real-number implementations (including the one here, I bet, but I haven't checked) will not
recognize that you're dividing something by itself. So you'll get a super-inefficient implementation of
the number 1 :-).
[EDITED to add:] I checked; the implementation here indeed won't recognize that you're dividing something by itself. For the avoidance of doubt, nor do I think trying to recognize such things would be an improvement.
(Also, if you ask for e.g. the digit immediately preceding the decimal point, you will wait for ever because no amount of precision will enable the implementation to tell whether your number is just less than 1 or 1 or just over. So don't ask it for that, ask it for a very close approximation and draw your own conclusions.)