This cannot shuttle between LEO stations and switch orbits to imitate multiple observation sats unless those sats and stations are very close in terms of orbits.
This cannot shuttle between LEO stations and switch orbits to imitate multiple observation sats unless those sats and stations are very close in terms of orbits.
Ref: https://www.military.com/daily-news/2019/07/23/former-secaf-...
It doesn’t have to return to orbit. Switching from an orbital trajectory to a parabolic intercept path would be feasible, and open valuable tactical space.
You can't gain delta-v by inducing additional drag on the craft.
Delta v a measurement of a vector, not a scalar. The fact that its kinetic energy with respect to Earth is decreasing does not mean it isn't gaining delta v. In addition to the obvious (lowering your apogee) you can also use this delta v to change your inclination. It's not "free" of course- you need to do other engine burns to both put the craft into the atmosphere and then another burn to reestablish orbit once you're out the other side. But it isn't clear to me that this is less efficient than just doing the burns without the atmospheric assists.
Yes and no. You've changed your velocity by 4km/s. You didn't gain usable ∆v, and you've just lost your spacecraft.
∆v means few related things. One, the amount of velocity change your mission plan requires. Second, the velocity change your craft is capable of using its own propulsion. Say you're plotting Mars orbit insertion. It requires (via [0]) 1.5 km/s ∆v. But you're a cheater, and decided to use aerobraking to bleed off (guessing a number) 1km/s of that velocity. This means you can complete this maneuver with a craft that only has 500m/s ∆v at the point of insertion. This does not mean the craft has gained ∆v.
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[0] - https://www.reddit.com/r/space/comments/29cxi6/i_made_a_delt...
Thinking "you're in space so can go anywhere" makes as much sense as thinking it's easy to go from Canada to the top of the Everest just because they're both on land.
I think you only need very little delta V to plunge back into the atmosphere from LEO.
The question is how much lift vs drag + delta V to lower and the raise you periapsis.
I think the space shuttle only had about 250m/s delta v once the yellow tank was exhausted, so those 250 m/s were enogh to complete both rasing the periapsis and then lowering it to de-orbit.
Think of a space-glider with one tip of its wings pointed straight down and the other straight up, if it has very little drag and a lot of lift, it could use its wings to maneuver north-south, change its orbital inclination, then when it gets out of the atmosphere again, once it reaches apoapsis it will spend some fuel to raise its periapsis again above the atmosphere, but KSP intuition is that if drag is low enough and lift is high enough, it could be better than to do an inclination change in vacuum.
As for mechjeb in particular, I never found it all that useful except when calculating rendezvous. I could do it myself, but I don’t want to bother with a protractor and calculator.
Timing a 30s burn when the probe takes 15m to get the signal is rather irritating.
https://www.space.com/9000-secret-37b-space-plane-changed-or...
https://www.popularmechanics.com/military/a28496447/x-37b-di...
http://spaceflight101.com/x-37b-space-plane-maneuvers-into-l...
You could have a few shuttles up there idling in various orbits ready to do a small number of bigger maneuvers to achieve a mission.
Alternatively you could have shuttles doing a whole lot rather slowly with electric propulsion.
Alternatively, thinking about the Earth's magnetic field, what if it had a big current loop that could be activated to generate a force and change orbit.
I realize that the magnitude of these effects are probably too small to be significant, but could you in principle use them to repeatedly change orbit around earth, provided you have an abundant energy source?
magnetic field? yes. - https://en.wikipedia.org/wiki/Electrodynamic_tether
http://www.esa.int/Our_Activities/Space_Engineering_Technolo...