I suppose my question is - all things being relative, why aren't the neutrinos bound to the same frame as the emitter and detector?
I suppose my question is - all things being relative, why aren't the neutrinos bound to the same frame as the emitter and detector?
I also see now that I misread the grand-parent post. Of course these motions would not affect the measurements, and if they did, the rotation of the earth alone would be obvious.
I'm sure that the effects are tiny for the LHC, but are they accounted for at all?
Actually no. The speed of light is constant in ALL frames of reference, whether inertial or not. The math just gets more complicated in non-inertial frames. (That's the difference between special and general relativity.)
UPDATE: it's actually a little more complicated than that. See http://en.wikipedia.org/wiki/Propagation_of_light_in_non-ine...
> I'm sure that the effects are tiny for the LHC
Actually, gravity is a pretty significant factor. See e.g.:
http://www.astronomy.ohio-state.edu/~pogge/Ast162/Unit5/gps....