Hacker News Reader

Comment by KMag | Hacker News Reader

C#'s % is explicitly the remainder operator, not the modulo operator.

Not according to reflection.

    Expression<Func<int, int>> lambda = n => n % 2;
    Console.WriteLine(((dynamic)lambda).Body.NodeType);

Output is "Modulo".

Hmm... I haven't read the official spec, just the Microsoft documentation: https://learn.microsoft.com/en-us/dotnet/csharp/language-ref... In any case, the behavior is rem, not mod.

Ada has both rem and mod operatiors. I'm not sure how many other languages have operators for both.

Ecstasy uses % for modulo, and /% for divrem (division and remainder). So "a = b % c" for calculating the modulo, but "(a, r) = b /% c" to get the divisor and remainder.

Reply on news.ycombinator.com