https://github.com/openai/math/tree/main/preprints/The-Expon...
>We give a deterministic algorithm for exactly counting the satisfying assignments of an arbitrary k-CNF formula [in superpolynomial but subexponential time]
>We give a deterministic algorithm for exactly counting the satisfying assignments of an arbitrary k-CNF formula [in superpolynomial but subexponential time]
I'm genuinely shook at today's results, specially at the fact that there _is_ a constructive algorithm.
I've got some reading to do it seems...
The actual exponent OpenAI found was x/sqrt(x).