I don't see this working, if the prisoner who flipped the switch on is brought back into the room immediately after the counter turns it off, then that one prisoner will be assumed to be two different people.
> '"Now I want each of you to flick Switch A to the "On" position twice, and only twice. So if you go in there and Switch A is already on, that doesn't count. I want each of you to actually flick it "On" two times. You got that?"'