16 karma · joined November 12, 2015
It seems that nouns are created with "-" (merriam-webster agree with you).
a long-term solution is like a never-ending story.
Now, my question why neverending story (film) and not never-ending?
Education has many problems, and the majority of questions about it are unanswered or the real answer is today unknown.
I see nothing new here. But I must say that Perl 6 seems to be easier to learn than Perl 5 for beginners.
Also, sometimes I watch a TV series in which police is trying to solve a 50 years old closed case. What I find interesting is how sad the life of that people are, never a joke, sharp sound, short sentences, never a smile. Perhaps, it is a mirror of a society. In Spain the eyes of people are full of life, the doom is outside of our frontiers (or so I think).
"I'm still not great at English but I surely improved over 15 years": => (I have surely improved) or: I haven't mastered English yet, but I am sure I have improved a lot in the last 15 years.
Without to mention how trivial is to go back in the learning process as long as you stop talking / listening for a couple of weeks… => To top it all, if you stop talking/listening for a couple of weeks you begin going backward in the learning process.
My long term hope is that soon or later => My long term hope is that sooner or later.
Another reason I find myself. => Another reason why I find myself.
NEVER learn a new word without learning what is its sound. => (how it sounds)
I should say that the first step is to clone:
cd where_you_want_the_data_to_be_copied git clone ....
# and now start jupyter notebook with
jupyter notebook
# go to File/open/ and select the first section.
I see that I can edit the markdown. I translated the introduction to section 0, here it goes. Thanks for this tutorial. The graphics are nice.
### Sección 0: Introducción Bienvenido a "Bayesian Modelling in Python" - un tutorial para personas interesadas en técnica de estadística bayesiana con Python. La lista de secciones del tutorial se encuentra en la página web del projecto [homepage](https://github.com/markdregan/Hangout-with-PyMC3).
La estadística es un tema que en mis años de universidad nunca me gustó . Las técnicas frecuentistas que nos enseñaron (p-values, etc.) parecían rebuscadas y en última instancia di la espalda a este tema en el que no estaba interesado.
Esto cambió cuando descubrí la estadística Bayesiana - una rama de la estadística bastante diferente a la estadística frecuentista que se suele enseñar en la mayoría de las universidades. Mi aprendizaje se inspiró en numerosas publicaciones, blogs y videos. A los que se inician en la estadística bayesiana les recomendaría fervientemente los siguientes:
- [Doing Bayesian Data Analysis](http://www.amazon.com/Doing-Bayesian-Analysis-Second-Edition...) by John Kruschke - [Python port](https://github.com/aloctavodia/Doing_Bayesian_data_analysis) of John Kruschke's examples by Osvaldo Martin - [Bayesian Methods for Hackers](https://github.com/CamDavidsonPilon/Probabilistic-Programmin...) fue para mí una gran fuente de inspiración para aprender estadística bayesiana. En reconocimiento de la gran influencia que ejerció en mí, he adoptado el mismo estilo visual que se usa en BMH. - [While My MCMC Gently Samples](http://twiecki.github.io/) blog de Thomas Wiecki - [Healthy Algorithms](http://healthyalgorithms.com/tag/pymc/) blog de Abraham Flaxman - [Scipy Tutorial 2014](https://github.com/fonnesbeck/scipy2014_tutorial) de Chris Fonnesbeck
He creado este tutorial con la esperanza de que otros lo encontrarán útil y que les servirá para aprender técnicas bayesianas de la misma forma que me ayudaron a mí. Cualquier aportación de la comunidad corrección/comentario/contribución será bienvenida.
Example: Context = Numeric question about integer numbers and four operators, +, - ,, /
input = r'[0-9,\+,\-,\,\/]'
Proof if q divides b^n, then q * c = b^n => p/q = (p * c)/(q * c) = (p * c)/b^n = (p * c)e-n in base b.
Example: Express the fraction 7/18 (base 10), in base 60 and convert it to a floating point in base 60.
60 = 2^2 * 3^1 * 5^1, 18 = 2^1 * 3^2, look for c such that 18 * c is a power of 60. Observe that the factors of 60^2 all have exponents that are greater or equal than those of 18, so we can multiply 18 by the required factors to get (60^2). This way: 60^2 = (2^2 * 3 * 5)^2 = 2^4 * 3^2 * 5^2 = 18 * c = (2^1 * 3^2) * (2^3 * 3^0 * 5^2)= 18200, so we need to multiply by 200 the numerator and denominator of the initial fraction to get a new fraction whose denominator is a power of 60. Now 7/18 = (7 200)/(18 * 200) = 1400/(60^2) and 1400 = 23 * 60 + 20.
Finally 7/18 = 1400/(60^2) = 0.2360 in base 60.
We use the notation 00,01,02, ... 59 for the digits of base 60, so 2360 is a two digits number in base 60.
The asterisk used for multiplication is not shown in HN, don't know why.
If [P,NP-c] = [0,1] I see GI as 1/4, if GI is proven to be in P then I should say [P,NP-c] is now [1/4,1].
In order to reduce more that interval one should find a problem that people think has a probability of 0.5 to be in P and 0.5 to be in NP, if it is proven that problem is in P then the interval get reduced a lot more. Just trying to explain my perception of the intuitive complexity of algorithms.
cat -A - and here paste text, you can see what is going on.
Personal Opinion: Perhaps the Complexity Hierarchy is going to collapse since intuition is not so clear and perhaps the distance from P to NP is shrinking.